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16x^2-33x-16=0
a = 16; b = -33; c = -16;
Δ = b2-4ac
Δ = -332-4·16·(-16)
Δ = 2113
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-\sqrt{2113}}{2*16}=\frac{33-\sqrt{2113}}{32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+\sqrt{2113}}{2*16}=\frac{33+\sqrt{2113}}{32} $
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